A particle moves with a velocity →v=(5^i−3^j+6^k)ms−1 under the influence of a constant force →F=(10^i+10^j+20^k)N. The instantaneous power applied to the particle is
A
200 W
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B
320 W
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C
140 W
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D
170 W
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Solution
The correct option is C 140 W Instantaneous power is given by the dot product of Force and the velocity. P=→F⋅→v P=(10^i+10^j+20^k).(5^i−3^j+6^k) P=50−30+120=140W Option C.