A particle moving in the xy plane undergoes a displacement of →s=(2^i+3^j) while a constant force →F=(5^i+2^j)N acts on the particle. The work done by the force F is
A
l7 joule
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B
l8 joule
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C
16 joule
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D
15 joule
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Solution
The correct option is C 16 joule W=¯F.¯s=(5^i+2^j).(2^i+3^j)=10+6=16J.