Question

A projectile is thrown into space so as to have maximum possible range of $400m$. Taking the point of projection as the origin, the coordinate of the point where the velocity of the projectile is minimum is

• A. $(400,100)$
• B. $(200,100)$
• C. $(400,200)$
• D. $(200,200)$

Answer 1

The correct option is B $(200,100)$

Maximum possible range $R_{max}=400m$

Maximum height attained $H=\frac{R_{max}}{4}=100m$

The particle has minimum velocity at the top most point of its projectile motion whose co-ordinates are $(R_{max}/2,H)$

So, x co-ordinate $x=\frac{400}{2}=200m$

Y-co-ordinate $y=H=100m$