A radiation of energy $E$ falls on a metal whose threshold energy is $E_{0}$ . Then, the kinetic energy is given as:

\frac{E - E_{0}}{2}

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E - E_{0}

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E_{0} - E

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\frac{E}{E_{0}}

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Solution

The correct option is B $E - E_{0}$
We know that, $E = E_{0} + K . E .$
$∴ K . E . = E - E_{0}$

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