Question

A rectangular hall has a length of $40m$ and width of $14m$. If the hall is to be tiled using $70cm\times 40cm$ tiles then,

What will be the total cost at the rate of $₹40Pertile?$

Answer 1

The length of the rectangle $=40m$

The breadth of the rectangle $=14m$

Area of Rectangle $=l\times b$

$$\begin{gathered} =40\times 14 \\ =560 \end{gathered}$$

So, the area of the rectangle is $560m^2=560\times 10000=5600000c{m}^2$

Then we need to find the area of tiles

Area of tiles $=length\times breadth$

$$\begin{gathered} =70\times 40 \\ =2800 \end{gathered}$$

So, the Area of tiles is $2800c{m}^2$

Than the number of tiles $=\frac{AreaofRec\tan gle}{Areaoftiles}$

$$\begin{gathered} =\frac{5600000}{2800} \\ =2000 \end{gathered}$$

Total Cost $=Numberoftiles\times rateofpertiles$

$$\begin{gathered} =2000\times 40 \\ =80000 \end{gathered}$$

Hence, the total cost is $₹80000$