A skydiver of mass $60 k g$ is in free-fall. She covers $40 m$ in two seconds. Calculate the average rate of work done by gravity on the skydiver (take $g = 10 m s^{- 2}$ ).

8 k W

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10 k W

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12 k W

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14 k W

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Solution

The correct option is C $12 k W$
Given: mass of skydiver, $m = 60 k g$ , displacement, $s = 40 m$ , acceleration due to gravity, $g = 10 m s^{- 2}$ , and time, $t = 2 s$ .

Let the force of free fall be $F$ work done be $W$ .

Using Newton's second law of motion, force:
$F = m a = 60 \times 10 = 600 N$

Work done $= Force \times Displacement$
$\Rightarrow W = F \times s = 600 \times 40 = 24000 J$

Average rate of work done $= \frac{total work done}{total time taken}$
$\Rightarrow \frac{W}{t} = \frac{24000}{2} = 12000 W = 12 k W$
Therefore, the rate of work done is $12 k W$

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A skydiver of mass 60 kg is in free-fall. She covers 40 m in two seconds. Calculate the average rate of work done by gravity on the skydiver (take g=10 ms−2).

A skydiver of mass $60 k g$ is in free-fall. She covers $40 m$ in two seconds. Calculate the average rate of work done by gravity on the skydiver (take $g = 10 m s^{- 2}$ ).