A skydiver with mass of $60 k g$ is moving at a terminal speed of $40 m$ in $2 s e c o n d s$ . Rate of work done by gravity is _____. Take $g = 10 m s^{- 2}$

10 k W

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12 k W

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14 k W

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16 k W

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Solution

The correct option is B $12 k W$
Given: Mass of skydiver $m = 60 k g$
Acceleration due to gravity $g = 10 m s^{- 2}$
Rate of work done by gravity = $\frac{w o r k d o n e}{t i m e}$
Force applied by gravity $F = m g = 60 \times 10 = 600 N$

Work done in 2 seconds = Force $\times$ Displacement
$= (60 \times 10 \times 40) J$
So, power $= \frac{(60 \times 10 \times 40)}{2} W$

= 12000 $W$
= 12 $k W$

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