Question

A solid AB has zns structure if the radius of cation a is 100 pm what is the radius of a anion B

Answer 1

Radius ratio = r+/r- = A+/B-
A+ = r+= radius of cation = 100 pm
B- = r- = radius of anion = ?

Note-
AB has ZnS type of structure i.e AB has tetrahedral holes. Therefore,

Radius ratio
= r+/r- = A+/B- = 0.225
=> B- = A+ / 0.225 = 100 pm/0.225 = 444.44 pm