A solid compound XY has NaCl structure . If the radius of cation is 100pm the radius of anion will be

275.1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

322.5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

241.5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

165.7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 241.5
Radius ratio = $r^{+}$ / $r^{-}$ = 0.414

100/ $r^{-}$ = 0.414

$r B^{-}$ =100/0.414

= 241 pm

Suggest Corrections

Similar questions

N a C l

100 p m

Y^{+}

N a C l

(Y^{-})

A solid AB has NaCl type structure. If the radius of cation A is 100 pm, then the radius of the anion B will be

A B

N a C l

100 p m

B^{-}

(Y^{-})

Join BYJU'S Learning Program