Question

# A verandah of width $2.25m$ is constructed all along outside a room which is $5.5m$ long and $4m$ wide. Find: (i) the area of the verandah. (ii) the cost of cementing the floor of the verandah at the rate of $₹200per{m}^{2}.$

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Solution

## Step 1: Calculate the area of the room.The length of the room $\left(L\right)=5.5m$The breadth of the room $\left(B\right)=4m$Area of the room $=$ length $×$ breadth $=5.5×4\phantom{\rule{0ex}{0ex}}=22{m}^{2}$Step 2: Calculate the area of the verandah.The new length and breadth of the room when the verandah is included are$10mand8.5m$ respectively.A new area of the room when verandah is included $=10×8.5$ $=85{m}^{2}$The area of verandah $=$ Area of the room when verandah is included $–$ Area of the room $=85–22\phantom{\rule{0ex}{0ex}}=63{m}^{2}$Step 3: Calculate the cost of cementing the floor. The cost of cementing the floor of the verandah at the rate of $₹200per{m}^{2}.$Then the cost of cementing the $63{m}^{2}$ area of the floor of the verandah $=200×63$ $=₹12600$Hence, the area of the verandah is $63{m}^{2}$ and the cost of cementing the area of the floor of the verandah is $₹12600.$

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