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Hybridisation

a What is per...

Question

a) What is percentage composition of potassium chlorate (KClO₃).

Given:Atomic mass Of K=39,Cl=35.5andO=16

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Solution

Molar Mass of KCLO3
= 39 + 35.5 + 48 g
= 122.5 g .

So , percentage of Potassium ( K )
= 39 / 122.5 * 100 %
= 31.83 %

Now , percentage of Chlorine ( Cl )
= 35.5 / 122.5 * 100 %
= 28.97 %

So, finally, percentage of Oxygen ( O )
= 48 / 122.5 * 100 %
= 39.18 %

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Similar questions

Q. Calculate the percentage composition of potassium in potassium chlorate (

K C l O_{3}

).
Given: Atomic mass of K = 39, Cl = 35.5 and O = 16

Q. Calculate the percentage composition of oxygen in potassium calculate

(K C C O_{3})

(Alomic mass of

K = 39, C l = 35.5

O = 16

Q. Calculate the mass of oxygen obtained by complete decomposition of 10 kg of pure potassium chlorate (Atomic mass K = 39, O = 16 and Cl= 35.5)

Q. Potassium chlorate on heating decomposes as under:

2 K C l O_{3} △ - \to 2 K C l + 3 O_{2}

Calculate (i) volume of oxygen evolved at S.T.P. (ii) weight of potassium chloride formed, when

4.9 g

of potassium chlorate decomposes completely.

[K = 39; O = 16; C l = 35.5]

Calculate the percentage composition of each element in Potassium chlorate, $K C l O_{3}$

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