Question

a) What is percentage composition of potassium chlorate (KClO₃).

Given:Atomic mass Of K=39,Cl=35.5andO=16

Answer 1

Molar Mass of KCLO3
= 39 + 35.5 + 48 g
= 122.5 g .

So , percentage of Potassium ( K )
= 39 / 122.5 * 100 %
= 31.83 %

Now , percentage of Chlorine ( Cl )
= 35.5 / 122.5 * 100 %
= 28.97 %

So, finally, percentage of Oxygen ( O )
= 48 / 122.5 * 100 %
= 39.18 %