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Question

Question 60 (a)

What should be subtracted from 2x33x2y+2xy2+3y3 to get x32x2y+3xy2+4y3?

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Solution

In order to get the solution, we will subtract x32x2y+3xy2+4y3 from 2x33x2y+2xy2+3y3.
Required expression is
2x33x2y+2xy2+3y3(x32x2y+3xy2+4y3)= 2x33x2y+2xy2+3y3x3+2x2y3xy24y3
On combining the like terms.
=2x3x33x2y+2x2y+2xy23xy2+3y34y3=x3x2yxy2y3
So, if we subtract x3x2yxy2y3 from 2x33x2y+2xy2+3y3. then we get x32x2y+3xy2+4y3.


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