A wooden block of volume 1000cm3 is suspended from a spring balance. It weighs 12 N in air. It is suspended in water such that half of the block is below the surface of water. The reading of the spring balance is
A
10 N
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B
9 N
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C
8 N
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D
7 N
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Solution
The correct option is D 7 N Reading of the spring balance = Apparent weight of the block = Actual weight - upthrust = 12−Vinσg=12−500×10−6×103×10=12−5=7N.