A wooden box measures $20$ cm by $10$ cm by $9$ cm Thickness of wood is 1 cm Volume of wood to make the box ( in cubic cm) is:

792

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519

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2400

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1120

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Solution

The correct option is A $792$
Length $= 20 c m$ , Breadth $= 10 c m$ . Height $= 9 c m$
External volume of box $= 20 \times 10 \times 9 = 1800 c m^{2}$
Thickness of wood $= 1 c m$
Internal volume of box $= (20 - 2) (10 - 2) (9 - 2) = 1008 c m^{2}$
Thus, volume of wood $= 1800 - 1008 = 792 c m^{3}$

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A wooden box measures 20 cm by 10 cm by 9 cm Thickness of wood is 1 cm Volume of wood to make the box ( in cubic cm) is:

The correct option is A 792Length=20cm, Breadth=10cm. Height=9cmExternal volume of box=20×10×9=1800cm2Thickness of wood=1cmInternal volume of box=(20−2)(10−2)(9−2)=1008cm2Thus, volume of wood=1800−1008=792cm3

A wooden box measures $20$ cm by $10$ cm by $9$ cm Thickness of wood is 1 cm Volume of wood to make the box ( in cubic cm) is:

The correct option is A $792$
Length $= 20 c m$ , Breadth $= 10 c m$ . Height $= 9 c m$
External volume of box $= 20 \times 10 \times 9 = 1800 c m^{2}$
Thickness of wood $= 1 c m$
Internal volume of box $= (20 - 2) (10 - 2) (9 - 2) = 1008 c m^{2}$
Thus, volume of wood $= 1800 - 1008 = 792 c m^{3}$