After incurring a loss of $25 %$ , a man had $R S . 18000$ left with him.What was the amount of money he originally had?

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Solution

Loss % $= 25$ %
Amount of money left $= R s .18, 000$
now loss % $= \frac{a m o u n t o r i g i n a l - a m o u n t l e f t}{o r i g i n a l a m o u n t} \times 10$

let the original amount be $^{'} x^{'}$

$\frac{25}{100} = \frac{x - 18000}{x}$

$\frac{18000}{x} = 1 - 0.25 = 0.75$

$x = \frac{1800000}{0.75} = 24, 000. R s$

$∴$ amount of money left is $24, 000 R s$

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