All resistance are connected in the series. The current is flowing through circuit is 2A and battery is of 20 Volts. What is the power dissipated through one of the $4 Ω$ :

4 W

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8 W

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16 W

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32 W

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36 W

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Solution

The correct option is E 16 W
Given : $I = 2$ A
Power dissipated through $4 Ω$ $P = I^{2} R_{1} = 2^{2} \times 4 = 16$ W

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All resistance are connected in the series. The current is flowing through circuit is 2A and battery is of 20 Volts. What is the power dissipated through one of the 4Ω:

The correct option is E 16 WGiven : I=2 A Power dissipated through 4Ω P=I2R1=22×4=16 W

All resistance are connected in the series. The current is flowing through circuit is 2A and battery is of 20 Volts. What is the power dissipated through one of the $4 Ω$ :

The correct option is E 16 W
Given : $I = 2$ A
Power dissipated through $4 Ω$ $P = I^{2} R_{1} = 2^{2} \times 4 = 16$ W