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Standard XII

Physics

Applications of Horizontal and Vertical Components

An aeroplane ...

Question

An aeroplane is flying horizontally with a velocity of 600 km/h at a height of 1960 m. When it is vertically above a point A (point A on the ground), a bomb is released from it. The bomb strikes the ground at point B. The horizontal distance AB is

1.2 km

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0.33 km

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3.33 km

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33 km

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Solution

The correct option is C
3.33 km

Horizontal displacement of the bomb
AB = Horizontal velocity $\times$ time available
AB = u $\times$ $\sqrt{\frac{2 h}{g}}$ = 600 $\times$ $\frac{5}{18}$ $\times$ $\sqrt{\frac{2 \times 1960}{9.8}}$ = 3.33 km.

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An aeroplane is flying horizontally with a velocity of 600 km/h at a height of 1960 m. When it is vertically above a point A (point A on the ground), a bomb is released from it. The bomb strikes the ground at point B. The horizontal distance AB is

The correct option is C 3.33 km Horizontal displacement of the bomb AB = Horizontal velocity × time available AB = u × √2hg = 600× 518×√2×19609.8 = 3.33 km.

The correct option is C
3.33 km

Horizontal displacement of the bomb
AB = Horizontal velocity $\times$ time available
AB = u $\times$ $\sqrt{\frac{2 h}{g}}$ = 600 $\times$ $\frac{5}{18}$ $\times$ $\sqrt{\frac{2 \times 1960}{9.8}}$ = 3.33 km.