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Question

An aeroplane is flying horizontally with a velocity of 600 km/h at a height of 1960 m. When it is vertically at a point A on the ground, a bomb is released from it. The bomb strikes the ground at point B. The distance AB is

A

1200 m

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B

0.33 km

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C

3.33 km

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D

33 km

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Solution

The correct option is C. 3.33 km.

The velocity with which the bomb is released is 600 km/h (horizontal).

Vertical velocity of the bomb is zero. Therefore using the second equation of motion we get,

h=ut+12gt2

h=0+12gt2

t=2hg

Horizontal displacement of the bomb
AB = Horizontal velocity × time available
AB=u×2hg=600×518×2×19609.8=3.33km.


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