An electric discharge is passed through a mixture containing 50 c.c. of $O_{2}$ and 50 c.c. of $H_{2}$ . The volume of the gases formed (i) at room temperature and (ii) at 110⁰C will be

(i) 25 c.c. (ii) 50 c.c.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(i) 50 c.c. (ii) 75 c.c.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(i) 25 c.c. (ii) 75 c.c.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(i) 75 c.c. (ii) 75 c.c.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C (i) 25 c.c. (ii) 75 c.c.
At room temperature $\begin{matrix} 2 H_{2 (g)} + & O_{2 (g)} \to & 2 H_{2} O_{l} t = 0 & 50 m l & 50 m l & 0 t = t & 50 - 2 x & 50 - x & 2 x = 0 & 25 g a s e s (50) l i q u i d \end{matrix}$
In this case $H_{2}$ is limiting reagent
$x = 25 m l$
At $110^{\circ} C$ $\begin{matrix} 2 H_{2 (g)} + & O_{2 (g)} \to & 2 H_{2} O_{(g)} & V_{g a s} = 75 m l t = t & 0 & 25 m l & 2 \times 50 m l \end{matrix}$

Suggest Corrections

Similar questions

An electric discharge is passes through a mixture containing 50 c.c. of $H_{2}$ and 50 c.c. of $O_{2}$ . The volume of the gases formed (i) at room temperature and (ii) at $110^{\circ} C$ will be:

Q. An electric discharge is passed through a mixture containing 50 c.c. of

O_{2}

and 50 c.c. of

H_{2}

. The volume of the gases formed (i) at room temperature and (ii) at 110⁰C will be

Q. An electric discharge is passed through a mixture containing 50 cc of

O_{2}

and 50 cc of

H_{2}

. The volume of the gases formed (i) at room temperature, (ii) at 110C will be:

Q. An electric discharge is passed through a mixture contaning

50

cc of

O_{2}

and

50

cc of

H_{2}

. The volume of the gases formed (i) at room temperature and (ii) at

110^{0} C

will be, respectively:

An electric discharge is passed through a mixture containing 50 cc of $O_{2}$ and 50 cc of $H_{2}$ . The volume of the gas formed (i) at room temperature (ii) at $110^{\circ} C$ will be:

(All measurements are made at same pressure and temperature)

Join BYJU'S Learning Program

An electric discharge is passed through a mixture containing 50 c.c. of O2 and 50 c.c. of H2. The volume of the gases formed (i) at room temperature and (ii) at 1100C will be

The correct option is C (i) 25 c.c. (ii) 75 c.c.At room temperature 2H2(g)+O2(g)→2H2Olt=050ml50ml0t=t50−2x50−x2x=025 gases (50) liquid In this case H2 is limiting reagent x=25 ml At 110∘C 2H2(g)+O2(g)→2H2O(g)Vgas=75 mlt=t025ml2×50ml

An electric discharge is passed through a mixture containing 50 c.c. of $O_{2}$ and 50 c.c. of $H_{2}$ . The volume of the gases formed (i) at room temperature and (ii) at 110⁰C will be