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Question
An equilateral triangle ABC is inscribed in a circle with centre O. Then, ∠BOC is equal to:
An equilateral triangle ABC is inscribed in a circle with centre O. Then, ∠BOC is equal to:
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Solution
The correct options are
B 60°
D 120°
Given, △ABC is an equilateral triangle.
⇒∠BAC=60∘
Since, the angle subtended by a chord at the centre of a circle is twice the angle subtended by the same chord at any other point on the remaining part of the circle.
So, ∠BOC=2×∠BAC=120∘
B
60°
D
120°
Given, △ABC is an equilateral triangle.
⇒∠BAC=60∘
Since, the angle subtended by a chord at the centre of a circle is twice the angle subtended by the same chord at any other point on the remaining part of the circle.
So, ∠BOC=2×∠BAC=120∘
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