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Standard XII

Chemistry

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An organic co...

Question

An organic compound (A) of molecular formula $C_{7} H_{8}$ on oxidation with air and in presence of $V_{2} O_{5}$ to form (B) of molecular formula $C_{7} H_{6} O$ . (B) on reduction with lithium aluminum hydride to form (C) of molecular formula $C_{7} H_{8} O$ . Identify (A), (B) and (C) and explain the reactions.

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Solution

$C_{7} H_{8} A a i r \to V_{2} O_{5} C_{7} H_{6} O B L i A l H_{4} \to C_{7} H_{8} O C$
$C_{6} H_{5} C H O B [H^{-}] \to C_{6} H_{5} C H_{2} O H C$
Benzaldehyde reduces to benzyl alcohol by $N a B H_{4}$ or $L i A l H_{4}$ .
A
is $C_{7} H_{8}$ $\to$
$C_{6} H_{5} C H_{3}$
Toluene
B
is $C_{7} H_{6} O$ $\to$
$C_{6} H_{5} C H O$
Benzaldehyde
C
is $C_{7} H_{8} O$ $\to$
$C_{6} H_{5} C H_{2} O H$
Benzylalcohl

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A	is $C_{7} H_{8}$ $\to$	$C_{6} H_{5} C H_{3}$	Toluene
B	is $C_{7} H_{6} O$ $\to$	$C_{6} H_{5} C H O$	Benzaldehyde
C	is $C_{7} H_{8} O$ $\to$	$C_{6} H_{5} C H_{2} O H$	Benzylalcohl

An organic compound (A) of molecular formula C7H8 on oxidation with air and in presence of V2O5 to form (B) of molecular formula C7H6O. (B) on reduction with lithium aluminum hydride to form (C) of molecular formula C7H8O. Identify (A), (B) and (C) and explain the reactions.

C7H8Aair→V2O5C7H6OBLiAlH4→C7H8OCC6H5CHOB[H−]→C6H5CH2OHCBenzaldehyde reduces to benzyl alcohol by NaBH4 or LiAlH4.A is C7H8 → C6H5CH3TolueneB is C7H6O → C6H5CHOBenzaldehydeC is C7H8O →C6H5CH2OH Benzylalcohl