Arrange $H C l O_{3}, H B r O_{3}$ and $H I O_{3}$ in the order of acidic strength.

H C l O_{3} > H B r O_{3} > H I O_{3}

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H B r O_{3} > H I O_{3} > H C l O_{3}

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H I O_{3} > H B r O_{3} > H C l O_{3}

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H C l O_{3} > H I O_{3} > H B r O_{3}

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Solution

The correct option is D $H C l O_{3} > H B r O_{3} > H I O_{3}$
$C l, B r, I$ all, belong to the same group. As one goes down the group, the atomic size increases and electronegativity decreases. Electronegativity is the ability of an atom to pull electrons towards itself.
Acid strength order :
$H C l O_{3} > H B r O_{3} > H I O_{3}$
Stability of their conjugates :
$C l O_{3}^{-} > B r O_{3}^{-} > I O_{3}^{-}$

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Arrange the following compounds according to the increasing order of oxidation state of chlorine.

$H C l O_{4}, H C l O_{3}, H C l O_{2}, H C l O$

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H C l O_{4}

H C l O_{4}, H C l O_{3}, H C l O_{2}, H C l O

H C l O_{4}

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