Arrange the following carbocations in decreasing order of stability

IV > III > I > V > II

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IV > I > III > II > V

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V > IV > I > III > II

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V > IV > III > I > II

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Solution

The correct option is C V > IV > I > III > II
Cyclopropylmethyl carbocation is especially stable because of conjugation between the bent orbitals of the cyclopropyl ring and the vacant p-orbitals of the cationic carbon. Thus

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