Question

Assuming the energy released per fission of $U^{235}$ is 200 me V , the energy released in the fission of 1 kg of $U^{235}$ is energy

• A. $0.91\times {10}^{11}J$
• B. $0.91\times {10}^{13}J$
• C. $8.19\times {10}^{11}J$
• D. $8.19\times {10}^{13}J$

Answer 1

The correct option is D $8.19\times {10}^{13}J$

Given,

Energy released per atom, $E=200MeV=200\times {10}^6\times 1.6\times {10}^{-19}=3.2\times {10}^{-11}J$

Number of atom in $1kg$ uranium, $n=\frac{m{N}_A}{M}=\frac{1000\times 6.023\times {10}^{23}}{235}=2.56\times {10}^{24}$

Total Energy released = $nE=2.56\times {10}^{24}\times 3.2\times {10}^{-11}=8.19\times {10}^{13}J$

Hence, Total Energy released = $8.19\times {10}^{13}J$.