At STP 89.6 L of chlorine gas reacts with 560 g of KOH according to the following sequential reaction. Calculate the number of grams of KClO4. Molar mass of KClO4=138.5 g mol−1
Molar mass of KOH=56 g mol−1
Cl2+2KOH→KCl+KClO+H2O
3KClO→2KCl+KClO3
4KClO3→KCl+3KClO4