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Question

# From the following reaction sequence: Cl2+2KOH→KCl+KClO+H2O 3KClO→2KCl+KClO3 4KClO3→3KClO4+KCl Calculate the mass of chlorine that reacts with an excess of KOH needed to produce 100 g of KClO4.

A
195.05 g
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B
205.05 g
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C
280.66 g
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D
328.78 g
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Solution

## The correct option is B 205.05 gGiven reactions: 4KClO3→3KClO4+KCl 12KClO→8KCl+4KClO3 12Cl2+24KOH→12KClO+12H2O+12KCl Overall reaction: 12Cl2+24KOH→3KClO4+21KCl+12H2O Molar mass of KClO4=138.5 g 3 mol of KClO4 are formed from 12 mol of Cl2. 3×138.5 g of KClO4 is formed from 12×71 g of Cl2. So,100 g of KClO4 will be formed =12×71×1003×138.5=205.05 g of Cl2

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