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Question

From the following reaction sequence
Cl2 + 2KOH KCl + KClO + H2O
3KClO 2KCl + KClO3
4KClO3 3KClO4+KCl

Calculate the mass of chlorine needed to produce 100g of KClO4


A

205.05g

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B

210.05g

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C

200.05g

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D

215.05g

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Solution

The correct option is A

205.05g


The give reactions involve certain compounds which are not needed for calculations.
Balance the reaction in a way that the unnecessary compounds get cancelled.
12Cl2 + 24KOH 12KClO + 12KCl + 12H2O
12KClO 8KCl + 4KClO3
4KCIO3 3KClO4 + KCl
12Cl2 + 24KOH 3KClO4+ 21KCl + 12H2O
We cancel the compounds on either side of the arrow
From this final balanced equation
12 moles of Cl2 gives 3 moles of KClO4
12 × (35.5 × 2=71)g = 3 × (138.5)g
100g of KCIO4=100×12×713×138.5

100g of KClO4 gives 205.05g of Cl2


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