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Question

From the following reaction sequence:
Cl2+2KOHKCl+KClO+H2O
3KClO2KCl+KClO3
4KClO33KClO4+KCl
Calculate the mass of chlorine that reacts with an excess of KOH needed to produce 100 g of KClO4.

A
195.05 g
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B
205.05 g
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C
280.66 g
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D
328.78 g
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Solution

The correct option is B 205.05 g
Given reactions:
4KClO33KClO4+KCl
12KClO8KCl+4KClO3
12Cl2+24KOH12KClO+12H2O+12KCl

Overall reaction: 12Cl2+24KOH3KClO4+21KCl+12H2O

Molar mass of KClO4=138.5 g
3 mol of KClO4 are formed from 12 mol of Cl2.
3×138.5 g of KClO4 is formed from 12×71 g of Cl2.
So,100 g of KClO4 will be formed =12×71×1003×138.5=205.05 g of Cl2

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