By selling two transistors for Rs. $600$ , each a shopkeeper gains $20$ percent on one transistor and loses $20$ percent on the other. Find $C.P.$ of each transistor.

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Solution

$S P = R s 600$
gain $= 20$ %
Let $C P = x$
$\Rightarrow x + \frac{20}{100} x = 600 \Rightarrow \frac{120 x}{100} = 600 \Rightarrow x = \frac{600 \times 100}{120} = 500 ∴ C P = R s 500$
For the second transistor loss $= 20$ %
$x - \frac{20}{100} x = 600 \Rightarrow \frac{80 x}{100} = 600 \Rightarrow x = \frac{600 \times 100}{80} = 750$
$∴$ Cost of other transistor $= R s .750$

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By selling two transistors for Rs. 600, each a shopkeeper gains 20 percent on one transistor and loses 20 percent on the other. Find C.P. of each transistor.

SP=Rs600gain=20%Let CP=x⇒x+20100x=600⇒120x100=600⇒x=600×100120=500∴CP=Rs500For the second transistor loss=20%x−20100x=600⇒80x100=600⇒x=600×10080=750∴ Cost of other transistor =Rs.750

By selling two transistors for Rs. $600$ , each a shopkeeper gains $20$ percent on one transistor and loses $20$ percent on the other. Find $C.P.$ of each transistor.