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Standard XII

Chemistry

Percentage Composition

Calcium carbi...

Question

Calcium carbide is made in an electric-furnace by the following reaction :
$C a O + 3 C ⟶ C a C O_{2} + C O$
The crude product is usually $85 %$ $C a C_{2}$ and $15 %$ unreacted $C a O$ . How much $C a O$ should we start with to produce $450$ kg of crude product?
(Given that molecular weight of $C a = 40, C = 12, O = 16$ g/mol)

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Solution

$100$ g of crude product contains $\frac{15}{56} = 0.27$ moles of $C a O$ and $\frac{85}{64} = 1.3$ moles of $C a C_{2}$ .
Thus, to get $100$ g of crude mixture, we should start with $0.27 + 1.3 = 1.57$ moles of $C a O$ .
Thus, to get $450$ kg of crude mixture, we should start with $\frac{450}{100} \times 1.57 = 394$ kg of $C a O$ .

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Similar questions

Q. Calcium carbide is made in an electric-furnace by the reaction given below:

C a O + 3 C ⟶ C a C_{2} + C O

The crude product is usually

85 %

C a C_{2}

and

15 %

unreacted

C a O

.
How much

C a C_{2}

would this crude product contain?

[Given atomic mass of

C a = 40

amu,

C = 12

amu,

O = 16

amu]

Q. Calcium carbide is made in an electric furnace by the reaction:

C a O + 3 C ⟶ C a C_{2} + C O

The crude product is usually

85 %

C a C_{2}

and

15 %

unreacted

C a O

.
(a)The amount of

C a O

with which we should start to produce

450

kg of crude product is

x

kg.
(b) Amount of

C a C_{2}

which this crude product will contain is

y

kg.
The value of

x + y

in a nearest integer is :

Q. Crude calcium carbide,

C a C_{2}

, is made in an electric furnace by the reaction,

C a O + 3 C \to C a C_{2} + C O

The product contains 64%

C a C_{2}

and 36% unreacted

C a O

.
(Given that molecular weight of Ca = 40, C =12, O = 16)

Q. How much heat will be required to make

2 k g

of calcium carbide

(C a C_{2})

according to the following reaction?

C a O (s) + 3 C (s) \to C a C_{2} + C O (g)

The heats of formation of

C a O (s), C a C_{2} (s)

and

C O (g)

are

- 151.6, - 14.2, - 26.4 k c a l

respectively.

C a C_{2} + H_{2} O \to C a O + H C \equiv C H

n (C H \equiv C H) + n H_{2} \to - (C H_{2} - C H_{2})_{n} -

Polyethylene can be produced from calcium carbide according to the given sequence of reactions.
The mass of polyethylene that can be produced from

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kg of pure

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Calcium carbide is made in an electric-furnace by the following reaction :CaO+3C⟶CaCO2+COThe crude product is usually 85% CaC2 and 15% unreacted CaO. How much CaO should we start with to produce 450 kg of crude product? (Given that molecular weight of Ca=40,C=12,O=16 g/mol)

100 g of crude product contains 1556=0.27 moles of CaO and 8564=1.3moles of CaC2.Thus, to get 100 g of crude mixture, we should start with 0.27+1.3=1.57 moles of CaO.Thus, to get 450 kg of crude mixture, we should start with 450100×1.57=394 kg of CaO.