Question

# Crude calcium carbide, CaC2, is made in an electric furnace by the reaction, CaO+3C→CaC2+CO The product contains 64% CaC2 and 36% unreacted CaO. (Given that molecular weight of Ca = 40, C =12, O = 16)

A
11500 kg of CaO is to be added to the furnace charge for each 8000 kg of CaC2
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B
920 kg of CaO is to be added to the furnace charge for each 1000 kg of crude product
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C
708.2 kg of CaO is to be added to the furnace charge for each 1000 kg of CaC2
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D
910.3 kg of CaO is to be added to the furnace charge for each 1000 kg of crude product
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Solution

## The correct options are A 11500 kg of CaO is to be added to the furnace charge for each 8000 kg of CaC2 B 920 kg of CaO is to be added to the furnace charge for each 1000 kg of crude productThe reaction is: CaO(s)+3C(s)→CaC2(s)+CO(g) (A) Final product contains 64% CaC2 & 36% CaO Let mass of product is 100 g Mass of CaC2=64 g Mass of CaO=36 g Used mole of CaO= mole of CaC2 produced =6464 ∴ mass of CaO for producing 64 g CaC2=6464×56=56 g ∴ Initial total mass of CaO =56+36=92 g 64 g CaC2 obtained from = 92 g CaO ∴1 g CaC2 obtained from =9264 g CaO 8×106 g CaC2 obtained from = 9264×8×106=11500000 g For 8000 kg CaC2 requires=11500 kg CaO. (B) 100 g product requires CaO = 92 g 1 g product requires = 92100 106 g product requires = 92100×106 For 1000 kg (crude) product = 920 kg CaO.

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