Calculate the energy of photon (in J) of light having frequency 2.7×1013s−1?
A
2×10−21J
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B
1.7×10−20J
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C
3.4×10−21J
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D
3×10−20J
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Solution
The correct option is B1.7×10−20J Given, λ=2.7×1013s−1 Energy of one photon = hv, where h=Planck's constant = 6.626×10−34Js Energyof photon =6.626×10−34×2.7×1013 =17.89×10−21J =1.78×10−20J