Calculate the mass of lime obtained by heating 200g of 95% pure limestone.
Limestone is CaCO3(MM = 100u)
95% pure sample of 200g has (95100 × 200) = 190g of CaCO3.
CaCO3 Δ→ CaO + CO2
100 g 56 g
∴ 100g of CaCO3 will yield 56g of lime
∴ 190g of CaCO3 will yield (190×56100) = 106.4g of CaO