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Question

Calculate the mass of lime obtained by heating 200g of 95% pure limestone.



A

100g

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B

106.4g

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C

108.3g

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D

110.3g

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Solution

The correct option is B

106.4g


Limestone is CaCO3(MM = 100u)

95% pure sample of 200g has (95100 × 200) = 190g of CaCO3.

CaCO3 Δ CaO + CO2

              

(limestone)              (lime)

100 g                      56 g

  100g of CaCO3 will yield 56g of lime

190g of CaCO3 will yield (190×56100) = 106.4g of CaO


Chemistry

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