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Question

Calculate the mass of potassium chloride formed and the volume of oxygen evolved at 27C and 750 mm of mercury, when 24.5 g of potassium chlorate is heated.

A
24.5 g, 6.48 L
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B
19.2 g, 8.40 L
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C
14.9 g, 7.48 L
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D
34.53 g, 9.84 L
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Solution

The correct option is D 14.9 g, 7.48 L
2KClO32KCl+3O2

Moles of KClO3=24.5122.5=0.2

Moles of KCl=0.2

Mass of KCl=0.2×74=14.9 gm

Volume of O2=nRTP=32×0.2×0.0821×300750760=7.48 litres

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