Calculate the mass of potassium chloride formed and the volume of oxygen evolved at 27C and 750 mm of mercury, when 24.5 g of potassium chlorate is heated.
A
24.5 g, 6.48 L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
19.2 g, 8.40 L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
14.9 g, 7.48 L
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
34.53 g, 9.84 L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is D 14.9 g, 7.48 L 2KClO3→2KCl+3O2
Moles of KClO3=24.5122.5=0.2
Moles of KCl=0.2
Mass of KCl=0.2×74=14.9gm
Volume of O2=nRTP=32×0.2×0.0821×300750760=7.48litres