Calculate the percentage composition of oxygen in potassium calculate $(K C C O_{3})$ (Alomic mass of $K = 39, C l = 35.5$ & $O = 16$ )

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Solution

Molar mass of $K C l O_{3} = 122.5$

Now % of $K$ = $39 X 100 / 122.5 = 31.84$

% OF $C l$ = $35.5 X 100 / 122.5 = 28.98$

% of $O$ = $48 X 100 / 122.5 = 39.18$

Hence,39.18 is the answer.

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Similar questions

Q. Calculate the percentage composition of potassium in potassium chlorate (

K C l O_{3}

).
Given: Atomic mass of K = 39, Cl = 35.5 and O = 16

a) What is percentage composition of potassium chlorate (KClO₃).

Given:Atomic mass Of K=39,Cl=35.5andO=16

Q. Calculate the mass of oxygen obtained by complete decomposition of 10 kg of pure potassium chlorate (Atomic mass K = 39, O = 16 and Cl= 35.5)

Q. Potassium chlorate on heating decomposes as under:

2 K C l O_{3} △ - \to 2 K C l + 3 O_{2}

Calculate (i) volume of oxygen evolved at S.T.P. (ii) weight of potassium chloride formed, when

4.9 g

of potassium chlorate decomposes completely.

[K = 39; O = 16; C l = 35.5]

Calculate the relative molecular masses of (Use K = 39, Cl = 35.5, O = 16, C = 12, H = 1, Na = 23, N = 14, S = 32)
(a) potassium chlorate
(b) sodium acetate
(c) chloroform
(d) ammonium sulphate

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Calculate the percentage composition of oxygen in potassium calculate (KCCO3) (Alomic mass of K=39,Cl=35.5 & O=16)

Molar mass of KClO3=122.5Now % ofK=39X100/122.5=31.84% OF Cl =35.5X100/122.5=28.98% of O =48X100/122.5=39.18Hence,39.18 is the answer.

Calculate the percentage composition of oxygen in potassium calculate $(K C C O_{3})$ (Alomic mass of $K = 39, C l = 35.5$ & $O = 16$ )

Molar mass of $K C l O_{3} = 122.5$

Now % of $K$ = $39 X 100 / 122.5 = 31.84$

% OF $C l$ = $35.5 X 100 / 122.5 = 28.98$

% of $O$ = $48 X 100 / 122.5 = 39.18$

Hence,39.18 is the answer.