Calculate the percentage of platinum in ammonium chloroplatinate (NH4)2PtCl6.
Atomic weight of platinum is 195 g. Molecular mass of (NH4)2PtCl6 = [2(14 + 4) + 195 + 6(35.5)] g = 444 g Percentage of platinum=Mass of platinum in the compoundMolecular mass of the compound×100Percentage of platinum=195444×100=43.99≈44%
Calculate the percentage of platinum in ammonium chloroplatinate, (NH4)2PtCl6.
(Give your answer correct to the nearest whole number).
[N= 14,H= l,Pt= 195,C1 = 35.5]
Calculate the relative molecular masses of :
(a) CHCl3 (b) (NH4)2Cr2O7
(c) CuSO4.5H2O (d) (NH4)2SO4
(e) CH3COONa (f) Potassium chlorate
(g) Ammonium chloroplatinate (NH4)2PtCl6