Question

$C{H}_3-C{H}_2-C{H}_2-C{H}_2-Br+C{H}_3{O}^{-}\underset{{60}^{o}C}{\overset{C{H}_{3}OH}{\to }}Product\left(I\right)$

$C{H}_3-C{H}_2-C{H}_2-C{H}_2-Br+\left(C{H}_3{)}_{3}C{O}^{-}\underset{{60}^{o}C}{\overset{(C{H}_3{)}_{3}C-OH}{\to }}Product\right(II)$

Select the correct options among the following.

• A. $C{H}_3{O}^{-}$ is a good nucleophile as well as a strong base and the primary bromide is converted into ether in the reaction (I)
• B. $C{H}_3{O}^{-}$ is a good nucleophile as well as a strong base forming the corresponding alkene in the reaction (I)
• C. primary bromide is attacked by the bulky strong base forming the corresponding alkene in the reaction (II)
• D. primary bromide is attacked by the bulky good nucleophile forming the corresponding ether

Answer 1

Answer: (A), (C)

$C{H}_3{O}^{-}$ is a good nucleophile as well as a strong base and the primary bromide is converted into ether in the reaction (I)
primary bromide is attacked by the bulky strong base forming the corresponding alkene in the reaction (II)

$C{H}_3{O}^{-}$ is a good nucleophile as well as a strong base as it has negative charge.

In reaction I, ether forms as product but when bulky group reacts with alkyl bromide, they forms alkene as a product.