Question

Construct a $△ABC$, when $AB=AC,BC=6.0cm$ and $\angle B={45}^{\circ }$

Answer 1

Step 1: Draw a line $BC$ of $6.2cm$

Step 2: Construct ${45}^o$ at $B$ and $C$ as it is given that $AB=AC$

Step 3: Name the point of intersection of two lines as $A$ and join $AB$ and $AC$.

$△ABC$ is the required triangle.