$Δ P Q R$ is an equilateral triangle an incircle with centre $O$ . Find the measure of $∠ P O R =$ ?

60^{\circ}

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120^{\circ}

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(180 + 60)^{\circ}

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(180 - 120)^{\circ}

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Solution

The correct option is B $120^{\circ}$
As it is equilateral triangle angle at O 360 degree is divided into three equal parts
therefore angle POR=120degree

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