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Question

ex(2x35x+10)dx=

A
ex(2x36x2+7x+3)+c
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B
ex(2x3+6x27x13)+c
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C
ex(2x36x2+7x13)+c
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D
ex(2x3+6x2+7x+13)+c
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Solution

The correct option is A ex(2x36x2+7x+3)+c
ex(2x35x+10)dx
2x35x+10=(ax3+bx2+cx+d)+(3ax2+2bx+c)
a=2;b+6=0b=6;c+2b=5c=7;d+c=10d=3
2x35x+10=(2x36x2+7x+3)+(6x212x+7)
ex(2x35x+10)dx=ex[(2x36x2+7x+3)+(6x212x+7)]dx
It is in the form of ex(f(x))+f(x)]dx=exf(x)+c
=ex(2x36x2+7x+3)+c

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