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Factorisation by Regrouping Terms

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Question

Factorise by grouping method:

$x (6 x - 5 y) - 4 (6 x - 5 y)^{2}$

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Solution

$x (6 x - 5 y) - 4 (6 x - 5 y)^{2}$

= (6x - 5y)[x - 4(6x - 5y)]

= (6x - 5y)(x - 24x + 20y) [Taking (6x - 5y) common from the three terms]

= (6x - 5y)(-23x + 20y)

= (6x - 5y)(20y - 23x)

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Similar questions

Q. Factorize the following equation by the grouping method

x (6 x - 5 y) - 4 {(6 x - 5 y)}^{2}

x (6 x - 5 y) - 4 (6 x - 5 y)^{2}

5 y^{2} + 5 y - 10

Q. Factorise:
(2x + 5y)² − 1

5 y^{2} + 5 y - 10

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Factorisation by Regrouping Terms

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