Factorize:
$3 a^{5} - 108 a^{3}$ .

3 a^{3} (a - 6) (2 a - 6)

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2 a^{3} (a + 6) (7 a - 6)

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2 a^{3} (a - 6) (3 a + 6)

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3 a^{3} (a + 6) (a - 6)

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Solution

The correct option is D $3 a^{3} (a + 6) (a - 6)$
$3 a^{5} - 108 a^{3}$
$= 3 a^{3} (a^{2} - 36)$
$= 3 a^{3} (a^{2} - 6^{2})$
$= 3 a^{3} (a + 6) (a - 6)$

Suggest Corrections

Similar questions

3 a^{5} - 108 a^{3}

3 a^{5} - 108 a^{3}

3 a^{2} - 9 a b

Factorise:

$3 a^{5} - 108 a^{3}$

36 a^{2} - 12 + \frac{1}{a^{2}}

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