Factorize each of the following algebraic expressions: 9a(6a−5b)−12a2(6a−5b)
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Solution
Given expression: 9a(6a−5b)−12a2(6a−5b)
∴9a(6a−5b)−12a2(6a−5b) =(6a−5b)(9a−12a2)
[taking (6a−5b) common ] =(6a−5b)(3×3×a−2×2×3×a×a) =(6a−5b)×3a(3−4a)
[taking 3a common from (9a−12a2)] =3a(3−4a)(6a−5b)