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Question

Factorize each of the following algebraic expressions:
9a(6a5b)12a2(6a5b)

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Solution

Given expression: 9a(6a5b)12a2(6a5b)

9a(6a5b)12a2(6a5b)
=(6a5b)(9a12a2)
[taking (6a5b) common ]
=(6a5b)(3×3×a2×2×3×a×a)
=(6a5b)×3a(34a)
[taking 3a common from (9a12a2)]
=3a(34a)(6a5b)

Hence, the factorized from is 3a(34a)(6a5b).

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