Factorize the following equation by the grouping method
$a (3 a - 2) - 1$

(a - 1) (3 a + 1)

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(a + 1) (a + 1)

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(a - 1) (3 a - 1)

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(a + 1) (a - 1)

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Solution

The correct option is A $(a - 1) (3 a + 1)$
$a (3 a - 2) - 1$
$= 3 a^{2} - 2 a - 1$
$= 3 a^{2} - 3 a + a - 1$
$= 3 a (a - 1) + 1 (a - 1)$
$= (a - 1) (3 a + 1)$

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