Question

Figure shows two capacitors connected in series and connected by a battery. The graph (B) shows the variation of potential as one moves from left and to right on the branch containing the capacitor. Then

• A. $C_1=C_2$
• B. $C_1<C_2$
• C. $C_1>C_2$
• D. $C_1$ and $C_2$ cannot be compared

Answer 1

The correct option is B $C_1<C_2$

According to the graph we can say that the potential difference across the capacitor $C_1$ is more than that across $C_2$

Since charge Q is same i.e,

$Q=C_1{V}_1=C_2{V}_2$

$\Rightarrow \frac{C_1}{C_2}=\frac{V_2}{V_1}$

$\Rightarrow C_1<C_2$ $(V_1>V_2)$