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Byju's Answer
Standard X
Mathematics
GCD of Polynomials
Find H.C.F an...
Question
Find H.C.F and L.C.M of
2
x
2
−
3
x
−
2
,
(
x
−
2
)
(
x
+
1
)
.
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Solution
Let
f
(
x
)
=
2
x
2
−
3
x
−
2
g
(
x
)
=
(
x
−
2
)
(
x
+
1
)
Factor of
2
x
2
−
3
x
−
2
=
(
2
x
+
1
)
(
x
−
2
)
So, H.C.F
=
(
x
−
2
)
L.C.M
=
(
x
−
2
)
(
2
x
+
1
)
(
x
+
1
)
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