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Question

Find H.C.F and L.C.M of 2x23x2, (x2)(x+1).

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Solution

Let f(x)= 2x23x2
g(x)= (x2)(x+1)
Factor of 2x23x2=(2x+1)(x2)
So, H.C.F = (x2)
L.C.M = (x2)(2x+1)(x+1)

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