Find the equation of the straight line with a slope of 3 and a y-intercept of 1

3x + y - 1 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3x - y + 1 = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x + 3y + 1 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x - 3y - 1 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

none of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 3x - y + 1 = 0
Equation of a straight line is
$y = m x + c$
Where $m$ is the slope of the line and $c$ is the $y$ intercept
Given,
$m = 3, c = 1$
$∴ y = 3 x + 1$
$=> 3 x - y + 1 = 0$

Suggest Corrections

Similar questions

y

x - 3 y + 1 = 0

- 1 / 3

y - i n t e r c e p t

- 4

x + 3 y + 5 = 0

- \frac{1}{3}

Join BYJU'S Learning Program