Find the maximum value of the magnitude of force F for which the system will move together. Take g=10m/s2.
A
20N
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B
30N
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C
50N
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D
75N
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Solution
The correct option is D75N The FBDs of the blocks are as shown. Given, the system of blocks will move together. From the FBDs we have N1=10g=100N N2=20g+N1=200+100=300N fmax=μsN1=0.5×100=50N
Now, for the blocks to move together, friction force required to be acted on block B is fmax=50N Hence, acceleration of the system is a=aB=fmaxmB=5020=2.5m/s2 ∴F=(mA+mB)a=30×2.5=75N