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Question

For the arrangement shown in the figure the tension in the string is
[Given: tan1(0.8)=39]

A
6 N
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B
6.4 N
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C
0.4 N
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D
Zero
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Solution

The correct option is D Zero
Here tanθ=0.8
where θ is angle of repose
θ=tan1(0.8)=39
The given angle of inclination is equal to the angle of repose. So the 1 kg block has no tendency to move.
mgsinθ= force of friction
T=0

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