For the redox reaction. $M n O_{4}^{-} + C_{2} O_{4}^{2 -} + H^{+} \to M n^{2 +} + C O_{2} + H_{2} O$ correct coefficient of the reactants are 2, 5,16.
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Solution

For the redox reaction. $M n O_{4}^{-} + C_{2} O_{4}^{2 -} + H^{+} \to M n^{2 +} + C O_{2} + H_{2} O$ correct coefficient of the reactants are 2, 5,16.
The reduction half reaction is
$M n O_{4}^{-} + 8 H^{+} + 5 e^{-} \to M n^{2 +} + 4 H_{2} O$
The oxidation half reaction is $C_{2} O_{4}^{2 -} \to 2 C O_{2} + 2 e^{-}$
The oxidation half reaction is multiplied with 5 and the reduction half reaction is multiplied with 2 and they are added to obtain the overall redox reaction.
The balanced chemical equation is as written below.
$2 M n O_{4}^{-} + 5 C_{2} O_{4}^{2 -} + 16 H^{+} \to 2 M n^{2 +} + 10 C O_{2} + 8 H_{2} O$

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